Trigonometri Sudut Rangkap
sin 2a = 2 sin a cos a
BUKTI
\begin{aligned}
\sin2a&=\sin(a+a)\\
&=\sin a\cos a+\cos a\sin a\\
&=\sin a\cos a+\sin a\cos a&{\color{red}\cos a\sin a=\sin a\cos a\text{ (sifat komutatif perkalian)}}\\
&=\boxed{\boxed{2\sin a\cos a}}
\end{aligned}
cos 2a = cos2 a − sin2 a = 1 − 2 sin2 a = 2 cos2 a − 1
BUKTI
\begin{aligned}
\cos2a&=\cos(a+a)\\
&=\cos a\cos a-\sin a\sin a\\
&=\boxed{\boxed{\cos^2 a-\sin^2 a}}\\
&=\cos^2 a-\left(1-\cos^2 a\right)\\
&=\cos^2 a-1+\cos^2 a\\
&=\boxed{\boxed{2\cos^2a-1}}
\end{aligned}
\begin{aligned}
\cos2a&=\cos^2 a-\sin^2 a\\
&=1-\sin^2 a-\sin^2 a\\
&=\boxed{\boxed{1-2\sin^2 a}}
\end{aligned}
\(\tan2a=\dfrac{2\tan a}{1-\tan^2a}\)
BUKTI
\begin{aligned}
\tan2a&=\tan(a+a)\\
&=\dfrac{\tan a+\tan a}{1-\tan a\cdot\tan a}\\
&=\boxed{\boxed{\dfrac{2\tan a}{1-\tan^2a}}}
\end{aligned}
sin 3a = 3 sin a − 4 sin3 a
BUKTI
\begin{aligned}
\sin3a&=\sin(2a+a)\\
&=\sin 2a\cos a+\cos 2a\sin a\\
&=\left(2\sin a\cos a\right)\cos a+\left(1-2\sin^2a\right)\sin a\\
&=2\sin a\cos^2a+\sin a-2\sin^3a\\
&=2\sin a\left(1-\sin^2a\right)+\sin a-2\sin^3a\\
&=2\sin a-2\sin^3a+\sin a-2\sin^3a\\
&=\boxed{\boxed{3\sin a-4\sin^3a}}
\end{aligned}
cos 3a = 4 cos3 a − 3 cos a
BUKTI
\begin{aligned}
\cos3a&=\cos(2a+a)\\
&=\cos 2a\cos a-\sin 2a\sin a\\
&=\left(2\cos^2a-1\right)\cos a-\left(2\sin a\cos a\right)\sin a\\
&=2\cos^3a-\cos a-2\sin^2 a\cos a\\
&=2\cos^3a-\cos a-2\left(1-\cos^2a\right)\cos a\\
&=2\cos^3a-\cos a-2\cos a+2\cos^3a\\
&=\boxed{\boxed{4\cos^3a-3\cos a}}
\end{aligned}
\(\tan3a=\dfrac{3\tan a-\tan^3a}{1-3\tan^2a}\)
BUKTI
\begin{aligned}
\tan3a&=\tan(2a+a)\\
&=\dfrac{\tan 2a+\tan a}{1-\tan 2a\cdot\tan a}\\[3.8pt]
&=\dfrac{\dfrac{2\tan a}{1-\tan^2a}+\tan a}{1-\left(\dfrac{2\tan a}{1-\tan^2a}\right)\tan a}\\[3.8pt]
&=\dfrac{\dfrac{2\tan a}{1-\tan^2a}+\dfrac{\tan a-\tan^3a}{1-\tan^2a}}{\dfrac{1-\tan^2a}{1-\tan^2a}-\dfrac{2\tan^2 a}{1-\tan^2a}}\\[3.8pt]
&=\dfrac{\dfrac{3\tan a-\tan^3a}{1-\tan^2a}}{\dfrac{1-3\tan^2a}{1-\tan^2a}}\\
&=\boxed{\boxed{\dfrac{3\tan a-\tan^3a}{1-3\tan^2a}}}
\end{aligned}
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